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                另类汉密尔顿路径                 </h1>
                <p>时间限制：10s&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  空间限制：128MB</p>			</div>
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                                <h3>题目描述</h3><p><p>无向图中的汉密尔顿是指一条路径，它经过每个点有且仅有一次。每条汉密尔顿路径的<br />
权值定义为这条路径中每条边的权值之和。这是最近 WZK 教小 Y 学的图论知识，现在 WZK<br />
想检验一下小Y的举一反三的能力，提出了以下问题： <br />
有一个n 个顶点的无向图（顶点从 0到 n-1 标号），它的每一个顶点都标有一个字符串<br />
label[i] ，两两顶点间都存在一条边，一条从 i 到 j 的 边 的 权 值 定 义 为<br />
length(label[i])^2+length(label[j])^2-length(LCP(label[i],label[j]))^2，LCP指的<br />
是两个字符串的最长公共前缀。现在，要求一个从顶点 0出发，到顶点 1结束的权值最小的<br />
汉密尔顿路径。</p>
<p></p></p><hr/><h3>输入格式</h3><p><p>&nbsp;第一行，一个整数 n (2&lt;=n&lt;=50)。 <br />
接下来n行，每行一个不超过 50个字母的小写字符串 label[i],i从0到n-1。 <br />
&nbsp;</p>
<p></p></p><hr/><h3>输出格式</h3><p><p>仅一行，为要求的汉密尔顿路径的权值。</p>
<p></p></p><hr/><h3>样例输入</h3><pre>4 
abcd 
aecgh 
abef 
aecd 

</pre><hr/><h3>样例输出</h3><pre>91
</pre><hr/><h3>提示</h3><p>没有写明提示</p><hr/><h3>题目来源</h3><p>没有写明来源</p>
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